Kinetic Energy Formula — KE = ½mv²

The kinetic energy formula KE = ½mv² explained: what each variable means, why speed is squared, assumptions and a worked example.

What it means

Kinetic energy grows with the square of speed: doubling the speed quadruples the energy. That is why a modest increase in driving speed makes crashes dramatically more violent — the energy the crumple zones and brakes must absorb scales as v2v^2. The one-half is not a fudge factor; it falls out of the calculus when you add up the work done over the whole acceleration. Mass enters only linearly, so at everyday speeds, going faster matters far more than being heavier.

Variables

SymbolNameUnitMeaning
KEKEKinetic energyJEnergy carried by the moving object
mmMasskgMass of the moving object
vvSpeedm/sMagnitude of the object's velocity

Assumptions

  • Object treated as a point mass (no rotation considered)
  • Speeds far below the speed of light (non-relativistic)
  • v is the speed relative to the chosen reference frame

Derivation

Start from the work-energy theorem: the work done accelerating a mass mm from rest to speed vv is W=∫F dx=∫ma dxW = \int F\,dx = \int ma\,dx. Writing a=v dv/dxa = v\,dv/dx turns the integral into m∫v dvm\int v\,dv, which evaluates to 12mv2\tfrac{1}{2}mv^2.

Worked example

Problem

A 70 kg runner sprints at 8 m/s. How much kinetic energy does she have?

Given:

  • m = 70 kg
  • v = 8 m/s
  1. Write the formula: KE=12mv2KE = \tfrac{1}{2}mv^2

  2. Substitute: KE=0.5×70×82KE = 0.5 \times 70 \times 8^2

  3. Calculate: 82=648^2 = 64, so KE=35×64=2240 JKE = 35 \times 64 = 2240\ \mathrm{J}

2240 J (2.24 kJ)

The runner carries 2240 joules of motion energy. To stop, that entire amount must be transferred somewhere — mostly into heat in the muscles and the ground with each braking stride.