RMS Speed — Nitrogen at Room Temperature (Worked Example)
Problem
Air is mostly nitrogen (M = 0.028 kg/mol). What is the root-mean-square speed of N₂ molecules at 300 K? (R = 8.314 J/(mol·K))
Given
T = 300 K
M = 0.028 kg/mol
R = 8.314 J/(mol·K)
Find
The rms speed v_rms.
Principle
Kinetic theory: temperature is molecular motion, v_rms = √(3RT/M).
Formula
v_rms = √(3RT/M)
Solution
Substitute:
Inside:
Square root:
517 m/s
Unit check
√(J/(mol·K) × K ÷ kg/mol) = √(m²/s²) = m/s — correct.
What this means physically
517 m/s — faster than a passenger jet, yet air feels still because molecules collide billions of times per second and go nowhere on average. Temperature is this motion.
Common mistake
Using M = 28 g/mol without converting. The formula needs kg/mol — 0.028, or the speed comes out ~31× too small.