Doppler Effect — Apparent Frequency Formula

The Doppler effect formula for a moving sound source — why sirens change pitch — with a worked ambulance example.

What it means

Motion squeezes or stretches waves: approaching motion bunches wavefronts together (higher frequency), receding motion spreads them (lower frequency). The top sign is for motion toward; the bottom for motion away. This shift reveals speeding cars, blood flow in ultrasound, and receding galaxies.

Variables

SymbolNameUnitMeaning
f′f'Observed frequencyHzFrequency the observer hears
ffSource frequencyHzTrue emitted frequency
vvWave speedm/sWave speed in the medium
vov_oObserver speedm/sObserver speed (positive toward source)
vsv_sSource speedm/sSource speed (positive toward observer)

Assumptions

  • Source and observer move along the line joining them
  • Speeds are far below the speed of sound
  • Medium (air) is still

Worked example

Problem

An ambulance siren emits 700 Hz while driving toward you at 30 m/s. What frequency do you hear? (Sound speed 343 m/s.)

Given:

  • f = 700 Hz (siren)
  • v = 343 m/s (sound in air)
  • v_s = 30 m/s toward observer
  • observer stationary (v_o = 0)
  1. Write the formula (source approaching): f′=fvv−vsf' = f\frac{v}{v - v_s}

  2. Substitute: f′=700×343343−30f' = 700 \times \frac{343}{343 - 30}

  3. Calculate: f′=700×343313=700×1.0958≈767 Hzf' = 700 \times \frac{343}{313} = 700 \times 1.0958 \approx 767\ \mathrm{Hz}

≈ 767 Hz

The pitch rises from 700 Hz to 767 Hz as the ambulance approaches — waves bunch up ahead of the source. After passing, the same formula with +v_s gives a lower pitch.