Snell's Law — n₁sinθ₁ = n₂sinθ₂

Snell's law n₁sinθ₁ = n₂sinθ₂ explained: refraction at boundaries, why light bends toward the normal, and a worked air-to-water example.

What it means

Snell's law governs every bend of light at a boundary. Light slows down in denser media, and to keep its wavefronts continuous across the interface, the ray must change direction — bending toward the normal when entering a slower medium, away when entering a faster one. When going from slow to fast at a steep enough angle, no real solution exists: that is total internal reflection, the principle behind fiber optics. Every lens, prism, rainbow and mirage is Snell's law in action.

Variables

SymbolNameUnitMeaning
n1n₁Index 1—Refractive index of the incident medium
θ1θ₁Angle 1degreesAngle of incidence, measured from the normal
n2n₂Index 2—Refractive index of the refracting medium
θ2θ₂Angle 2degreesAngle of refraction, measured from the normal

Assumptions

  • Sharp boundary between two uniform transparent media
  • Monochromatic light (single wavelength — n varies slightly with color)
  • Angles measured from the normal to the surface, not the surface itself

Derivation

Fermat's principle — light takes the path of least time — applied to a ray crossing an interface gives n1sin⁡θ1=n2sin⁡θ2n_1\sin\theta_1 = n_2\sin\theta_2 after minimizing the travel time. Equivalently, it follows from matching the wave's phase along the boundary.

Worked example

Problem

A light ray in air hits water at 45° to the normal. At what angle does it travel underwater?

Given:

  • n₁ = 1.00 (air)
  • θ₁ = 45°
  • n₂ = 1.33 (water)
  1. Write Snell's law: n1sin⁡θ1=n2sin⁡θ2n_1\sin\theta_1 = n_2\sin\theta_2

  2. Rearrange: sin⁡θ2=(n1/n2)sin⁡θ1\sin\theta_2 = (n_1/n_2)\sin\theta_1

  3. Substitute: sin⁡θ2=(1.00/1.33)×sin⁡45°\sin\theta_2 = (1.00/1.33) \times \sin 45°

  4. Calculate: sin⁡θ2=0.7519×0.7071=0.5317\sin\theta_2 = 0.7519 \times 0.7071 = 0.5317

  5. Take arcsine: θ2=sin⁡−1(0.5317)=32.1°\theta_2 = \sin^{-1}(0.5317) = 32.1°

θ₂ ≈ 32.1° from the normal

Entering the slower medium (water), the ray bends toward the normal — 45° becomes 32°. This bending is why a straw in a glass looks broken at the surface and why pools look shallower than they are.