Electrical Power — P = IV

P = IV — electrical power equals current times voltage. Use the p=iv formula to find watts in any circuit, with the I²R heating form and a worked bulb example.

What it means

Electrical power is the rate at which a circuit converts electrical energy into something else — light, heat, motion. Voltage tells you the energy per coulomb; current tells you coulombs per second; multiply them and you get energy per second. The rearranged form P=I2RP = I^2R explains why power lines run at enormous voltages: for fixed delivered power, higher voltage means lower current, and resistive heating losses fall as the square of the current. That single insight shapes the entire power grid.

Variables

SymbolNameUnitMeaning
PPPowerWRate of electrical energy conversion
IICurrentACurrent through the component
VVVoltageVVoltage across the component

Assumptions

  • Steady DC conditions (for AC use RMS values)
  • Component is ohmic if combining with V = IR
  • P is the power dissipated or delivered, not stored

Derivation

Power is energy per unit time. Each coulomb of charge dropping through voltage VV loses energy QVQV; with current I=Q/tI = Q/t charges per second, the energy rate is P=IVP = IV. Substituting Ohm's law gives the alternate forms P=I2R=V2/RP = I^2R = V^2/R.

Worked example

Problem

A light bulb draws 0.5 A from a 120 V supply. What power does it dissipate?

Given:

  • V = 120 V
  • I = 0.5 A
  1. Write the power formula: P=IVP = IV

  2. Substitute: P=120×0.5P = 120 \times 0.5

  3. Multiply: P=60 WP = 60\ \mathrm{W}

60 W

The bulb converts electrical energy into light and heat at 60 joules per second. Run it for one hour and it consumes 60 watt-hours — 0.06 kWh on your electricity bill.