Snell's Law — Light Escaping Diamond (Worked Example)

Problem

Light inside a diamond (n = 2.42) strikes the diamond–air surface at 30° to the normal. Does it refract out, or is it totally internally reflected?

Given

  • n₁ = 2.42 (diamond)

  • n₂ = 1.00 (air)

  • θ₁ = 30°

Find

Whether refraction is possible; the critical angle.

Principle

Snell's law n₁sinθ₁ = n₂sinθ₂: if sinθ₂ > 1, no refraction exists — total internal reflection. The critical angle is θc = arcsin(n₂/n₁).

Formula

Solution

  1. Try Snell: sin⁡θ2=(n1/n2)sin⁡θ1=2.42×sin⁡30°=2.42×0.5=1.21\sin\theta_2 = (n_1/n_2)\sin\theta_1 = 2.42 \times \sin30° = 2.42 \times 0.5 = 1.21

  2. Since 1.21>11.21 > 1, no real θ₂ exists — total internal reflection occurs

  3. Critical angle: θc=arcsin⁡(1/2.42)=arcsin⁡(0.413)=24.4°\theta_c = \arcsin(1/2.42) = \arcsin(0.413) = 24.4°

  4. Because 30° > 24.4°, the ray reflects entirely

Totally internally reflected (critical angle 24.4°)

Unit check

Angles in degrees throughout — consistent.

What this means physically

Total internal reflection — this light-trapping is why diamonds sparkle: rays bounce around inside instead of leaking out, exiting only through the top facets.

Common mistake

Computing θ₂ = arcsin(1.21) on a calculator and accepting an error. If sinθ₂ > 1, stop — that is the answer: TIR.